when a body is dropped freely from the top of the tower, the dist covered in the last 1s is equal to the dist covered in the first 3s ... find h of tower and the time taken to strike ground
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125 m
Explanation:
The distance covered in first 3 second
s=1/2gt2
=1/2×10×32
=45
If the ball takes 'n' second to fall to ground . The distance covered in nth second
sn=u+g/2(2n−1)
=0+10/2(2n−1)
=10n−5
Therefore 45=10n−5
n=5
Therefore h=12gt2
=12×10×25
=125m
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