Question

When a body is immersed in water it displaces 4 kg of water. how much is the buoyant force acting on the body?

Answer 1

GIVEN,
             Mass of the water =4kg
                                        g =10m/s^-2
        
                              =  Weight =m multiplied by g
                                            w= 4 multiplied by 10
                                            w= 40N
SINCE THE WEIGHT OF WATER DISPLAYED BY THE OBJECT IS 40N
THEREFORE THE BUOYANT FORCE ACTING ON THE OBJECT WILL 
ALSO BE 40N..

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