Question

When a body is placed on a rough plane inclined at an angle θ to the horizontal, its acceleration is?

Answer 1

(b) g(sin ­-- cos ) this is the answer

Answer 2

Hello buddy,

◆ Answer-
a = g(sinθ + μcosθ)

◆ Explaination-
[Refer to the figure]

Let a mass m be sliding over plane at angle θ.

Force acting on given mass is-
F = mgsinθ + μmgcosθ
F = mg(sinθ + μcosθ)

Acceleration of the body-
a = F/m
a = mg(sinθ + μcosθ) / m
a = g(sinθ + μcosθ)

Therefore,
Acceleration = g(sinθ + μcosθ)

Hope it helps...