Question

When a body is projected in air then at a point in air, it's horizontal and vertical velocities are 4&3 m/sec.
Calculate the resultant velocity.​

Answer 1

Answer:

$\huge\mathtt\pink{A}\mathtt\red{N}\mathtt\blue{S}\mathtt\green{W}\mathtt\purple{E}\mathtt\green{R} \:5m/sec$

Given:-

Horizontal component=4m/sec

Vertical component=3m/sec

To find :-

Resultant velocity

Solution:-

V=(4i+3j)m/sec

$|v| = \sqrt{ {3}^{2} + {4}^{2} } = 5$

Now finding direction

$\tan( \alpha ) = \huge \: \frac{v_x}{v_y}$

$\tan( \alpha ) = \huge \: \frac{4}{3}$

Hence

$\alpha = {53}^{0}$