When a body is projected vertically up from the ground, its velocity is reduced to 1/3rd of its initial velocity at heighth above the ground. Then maximum height reached by the body is-
Answers
Given : When a body is projected vertically up from the ground, its velocity is reduced to 1/3rd of its initial velocity at height h above the ground.
To Find : maximum height reached by the body
Solution:
Assume that initial velocity = 3v m/s
Velocity at height h = (1/3)3v = v m/s
V² - U² = 2aS
a = - g
S = h
V = v
U = 3V
=> v² - (3v)² = 2(-g)h
=> -8v² = - 2gh
=> v² = gh/4
Height at top ( Max) = H
Velocity at top = 0
0² - (3v)² = -2gH
=> 9v² = 2gH
=> 9gh/4 = 2gH
=> H = 9h/8
maximum height reached by the body is 9h/8
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Answer:
Assume that initial elocity=3v m/s Velocity at height h = (1/3)3v = v m/s
V ^ 2 - U ^ 2 = 2aS
a=-g
S = h
V = V
U = 3V
=> v² - (3v)² = 2(-g)h
=> -8v² = -2gh
=> v² = gh/4
Height at top (Max) = H
Velocity at top = 0
O ^ 2 - (3v) ^ 2 = - 2gH
=> 9v² = 2gH
=> 9gh/4 = 2gH
=> H = 9h/8