Question

When a body is projected vertically upward with a velocity V from the ground , its potential energy and kinetic energy at a height h above the ground are in the ratio 2:3.If the same body is projected again but with velocity 2v, it reaches a maximum height H.Find h:H.​

Answer 1

Answer:

Explanation:

you know relation between potential energy and kinetic energy

k.e=p^2/2m

suppose assume 2x=potential energy 3x=kinetic energy in case 1

2x=9x^2/m

m=9x/2

if you project with velocity 2v

means kinetic energy increases by 4 times

kinetic energy=4x  potential energy= we want to find  m=same

in this case

4x=P.E^2/9x/2

8x^2/9=P.E^2

8^1/3*1/3*x=P.E

h:H is means ratio of potential energy

3x: 2root2*1/3*x

9/2root 2

Answer 2

Answer:

Ratio of heights will be as h : H = 1: 4