Question

when a body is projected vertically upwards, its velocity
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Answer 1

Answer:

A body is projected vertically upwards wth a velocity `u=5m//s`. After time `t` another body. A body is projected vertically upwards wth a velocity `u=5m//s`. After time `t` another body is projected vertically upward from the same point with a velocity `v=3m//s`.

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Answer 2

QUESTION

When a body is projected vertically up from the ground its velocity is reduced to 1/4 th of its velocity at ground at height h. Then the maximum height reached by the body is -

SOLUTION

Using the equation of motion ,

v square = u square - 2gh

u square / 16 = u square - 2gh

h = 15 u square / 32g

At Max. height, v = 0 and equation of motion is

v square = u square - 2gh

H = u square / 2 g = 15 h / 16

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