Question

when a body of density D1 and volume V is floating in a liquid of density d2. 1- its true weight is vd2. 2-loss in its weight is vd2g. 3-its apparent weight is zero. 4-its density is greater than that of liquid d2​

Answer 1

Answer:

2

Explanation:

The liquid will apply an upthrust on it...thus its weight will reduce.

Now

U=V×d

This gives

U=VD2 ×g

Answer 2

Answer:

Option 3

Explanation:

It's apparent weight is zero