When a body of mass 1 kg is suspended from a certain light spring hanging vertically its length increase by 5 cm by suspending 2 kg block to the spring and if the block is pulled through 10cm?
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Answer:
Explanation:f=mg
3g=k(x+5)
1/3=x/x+5
X=2.5cm
10=k.2.5*10^2
K=400N
W=root k/m=400/3
Vmax=10*15^2*root400/3
=1.154m/s
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