Question

When a body of mass 10 kg increases it's velocity from 2m/s to 8m/s within 4 second .The magnitude of applied force

Answer 1

Force :

It is defined as mass times the acceleration .

$\bigstar\ \; \sf \huge{\red{F=ma}}$

Acceleration :

It is defined as rate of change in velocity .

$\bigstar\ \; \sf \huge{\green{a=\dfrac{v-u}{t}}}$

So ,

$:\implies \sf F=ma$

$:\implies \sf F=\dfrac{m(v-u)}{t}$

Given ,

Mass , m = 10 kg

Initial velocity , u = 2 m/s

Final velocity , v = 8 m/s

Time , t = 4 s

$:\implies \sf F=\dfrac{10(8-2)}{4}$

$:\implies \sf F=\dfrac{10(6)}{4}$

$:\implies \sf F=\dfrac{60}{4}$

$:\implies \sf \blue{F=15\ N}\ \; \bigstar$

So , Magnitude of the force applied is 15 N

Answer 2

Answer:

✡ Given ✡

$\leadsto$ When a body of mass is 10 kg increases it's velocity from 2 m/s to 8 m/s within 4 sec.

✡ To Find ✡

$\leadsto$ What is the magnitude of applied force.

✡ Formula Used ✡

⭐ F = $\dfrac{m(v - u)}{t}$ ⭐

✡ Solution ✡

Given:-

• m = 10 kg
• u = 2 m/s
• v = 8 m/s
• t = 4 sec

▶ According to the question by using the formula we get,

$\implies$ F = $\dfrac{10(8 - 2)}{4}$

$\implies$ F = $\dfrac{10(6)}{4}$

$\implies$ F = $\dfrac{60}{4}$

$\implies$ F = 15 N

$\therefore$ The magnitude of applied force is 15 N .

Explanation:

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