When a body of mass 10kg is compelled by a force of 20N .through a distance of 6m. Find the kinetic energy. please answer fast
Answers
Answered by
2
F=ma
20=10a
a=20/10
a=2 m/s^2
v×v=2× 2 × 6
v × v = 24
Kinetic energy =
0.5 × 10 × 24
120J
20=10a
a=20/10
a=2 m/s^2
v×v=2× 2 × 6
v × v = 24
Kinetic energy =
0.5 × 10 × 24
120J
bethelchazie:
Can u relate it with PE=KE i.e mgh = 0.5mv²
U can not say that PE=KE because its not correct all conditions
total energy = KE+PE
when total energy will be 0 then it is correct
Thanks
Similar questions