When a body of mass m is dropped from some height h, how the total energy is
conserved at the top, midway and when and body reaches the bottom first before
hitting the ground ?
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Answer:
Initial Energy of the body =K.E+P.E
KE
i
=0,PE
i
=mgh
Final Energy KE
f
+PE
f
PE
f
=0
Energy is conserved
Final Energy = Initial Energy
KE
f
=PE
i
=mgh
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