When a body starts from rest, the acceleration of the body after 2 seconds is _____one fourh __ of its displacement. (half, twice, four times, one-fourth) TNSCERT Class 9 General Science Ch 6 Motion
Answers
Answered by
11
v = u + at
After 2s
v = 0 + 2a
v = 2a
S = (v^2 - u^2) / (2a)
S = (v^2 - 0) / (2a)
S = (4a^2) / (2a) ………[∵ from Equation 1]
S = 2a
a = S/2
After 2s acceleration is half of its displacement.
In other words,
Acceleration of the body after 2s is TWICE of one-fourth of its displacement.
[∵ 2 * 1/4 = 1/2]
After 2s
v = 0 + 2a
v = 2a
S = (v^2 - u^2) / (2a)
S = (v^2 - 0) / (2a)
S = (4a^2) / (2a) ………[∵ from Equation 1]
S = 2a
a = S/2
After 2s acceleration is half of its displacement.
In other words,
Acceleration of the body after 2s is TWICE of one-fourth of its displacement.
[∵ 2 * 1/4 = 1/2]
Similar questions