when a bodyis projected with velocity 10 m/s. Then he attained maximum height is 20 m. if the ball is projected with velocity 20 m/s then he attain maximum height.
Answers
Q-A body projected vertically up with a velocity of 10ms^-1 reaches a height of 20m. If it is projected with the velocity of 20ms^-1 ,then what is the maximum height reached by the body?
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ANS-Thrown with a velocity of 10 m/s, if it reaches a height of 20 m, the g at that place must be g = v^2/ 2h = 100/ 40 = 2.5m/s^2
Thrown with a velocity of 20 m/s,it will reach a height of
h = v^2/(2g) = 400/5= 80 m
Or simply ,
H2 = ( v2/v1)^2*H1=4 *20 = 80m
A body projected vertically upwards with a velocity of 10m/s reaches a height of 20m if it is projected with a velocity of 20 m/s then what is the maximum height reached by the body?
A body released from height 'h' takes time 't' to reach the ground after time t/2, its height from the ground is?
A body is projected from the top of a tower that is 100m high with a speed of 20m/s in upward direction. How do you find the height attained by the body?
A body is thrown with some velocity from the ground to a height of 90 cm. What is the height reached when it is thrown at 30' to the horizontal?
What is the velocity at the maximum height when a body is projected vertically upwards?
h=v²/2g
20=100/2g
40g=100
g=100/40=2.5 m/s²
The time to max height is v/g, or 20/2.5=8 seconds
Then:
h(8)=g/2(8²)+20(8)
=-1.25(64)+160
=80m
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Maximum height (in vacuum) is proportional to the square of the initial velocity. If one increases velocity by a factor of 2 the height will increase by a factor of 4 ==> 4*20 m = 80 m
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