Question

When a bucket is filled 3/8 of its capacity its weight is 10 Kg. If it is filled 3/5 of its capacity,

its weight is 14.5 kg. How much will its weight be when it is filled to the full capacity ?​

Answer 1

Step-by-step explanation:

We can convert these fractions to exact decimals

3/8 = .375

3/5 = .6

:

Assign the values as follows

x1 = .375; y1 = 10

x2 = .600; y2 = 14.5

:

Find the slope m = y2-y1/x2-x1

m = 14.5-10/6-375 = 4.5/225 = 20

:

Use the point/slope form to construct an equation: y - y1 = m(x - x1)

y - 10 = 20(x - .375)

y - 10 = 20x - 7.5

y = 20x - 7.5 + 10

y = 20x + 2.5, is the equation

:

Bucket is full when x = 1

y = 20(1) + 2.5

y = 22.5 kg for a full bucket