Physics, asked by Saliq8822, 1 year ago

When a bullet is shot from a gun the velocity of require a gun is much lesser than the velocity at which the bullet moves out is it the violation of law of conservation of momentum

Answers

Answered by shiva8745
5
The gun has much more mass than the bullet. 

Think about the conservation of momentum. And Newton. Every action has an equal and opposite reaction. 

Momentum = Mass x Velocity. 

Total Momentum (bullet and gun together) starts off as Zero before the bullet is fired. It must stay that way after the bullet is fired. 

Since the bullet and the gun should have opposite and equal momentum, the velocity of the bullet is much greater since the mass is much smaller. 

- M(gun) x V(gun) + M(bullet) x V(bullet) = 0 

There is a negative sign in front of the gun-part of the equation, because the gun is moving backward. 

There is a positive sign in front of the bullet-part of the equation, because the bullet is moving forward. 

Rearrange the equation above => 
M(gun) x V(gun) = M(bullet) x V(bullet) 

B I G x small = small x B I G
Answered by pandeyalok52
0

When a bullet is shot from a gun the velocity of require a gun is much lesser than the velocity at which the bullet moves out is it the violation of law of conservation of momentum.

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