Question

When a bullet of 100 g is fired from a gun of 1.5 kg with the velocity of 25m/square find the recoil velocity

Answer 1

Explanation:

HEY MATE

Answer:

Answer:Mass of the rifle (m1) = 4 kgMass of the bullet (m2) = 50 g = 0.05 kgRecoil velocity of the rifle = v1A bullet is fired with an initial velocity (v2) = 35 m/sInitially, the rifle is at rest.Thus, its initial velocity (v) = 0Total initial momentum of the rifle and bullet system⇒ (m1+m2) × v = 0The total momentum of the rifle and bullet system after firing= m1 v1 + m2 v 2

2= (4 × v1 ) + (0.05 × 35)= 4v1 + 1.75According to the law of conservation of momentumTotal momentum after the firing = Total momentum before the firing4v1 + 1.75 = 0v1= -1.75 / 4v1 = – 0.4375 m/sThe negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s.

HOPE IT HELPS YOU