When a capacitor of capicity c is charged through a resistor?
Answers
When a capacitor is connected between the terminals of a powersupply (or cell) electrons are forced off of one of the capacitor’s plates and forced onto the opposite plate through the power supply.
Due to the action of the power supply which causes a current to flow electrons are forced off of the positive plate (hence there is a deficiency of negative charge and it gains an overall positive charge).
Electrons are simultaneously forced onto the negative plate by the power supply (accumulation of negative charges hence it gains overall negative charge).
Explanation:
Q=CV(1−e−t/(RC)). Thus the charge on the capacitor asymptotically approaches its final value CV, reaching 63% (1 - e-1) of the final value in time RC and half of the final value in time RCln2=0.6931RC. The potential difference across the plates increases at the same rate.