when a capacitor of value 200muf charged to 200V is discharged separatly through resistance of 2ohms and 8ohms, then heat produced in joule will respectively be
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Explanation:
explanation : capacitance of capacitor , C = 200 uF
potential across the capacitor , V = 200 volts.
heat produced due to discharged of capacitor of capacitor C which is placed across the voltage V is given by, H = 1/2 CV²
= 1/2 × 200uF × (200volts)²
= 100 × 10^-6 × 40000 J
= 4 J
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