Question

when a capillary is dipped into a liquid the levels of liquid inside and outside are equal the angle of contact is?

Answer 1

answer : 90°

explanation : we know, height rise of liquid in capillary tube is given by,

$h=\frac{2Tcos\theta}{\rho rg}$

where, h is height rise of liquid in capillary tube.

T is surface tension of liquid.

$\theta$ is angle of contact.

$\rho$ is density of liquid.

r is the radius of capillary tube.

and g is acceleration due to gravity.

a/c to question, a capillary is dipped into a liquid the levels of liquid inside and outside are equal.

then, h = 0 = $\frac{2Tcos\theta}{\rho rg}$

$cos\theta=0=cos90^{\circ}$

$\theta=90^{\circ}$

Answer 2

Answer:

hope it helps you thank you