Question

When a car driver travelling along a straight path at a speed of 10 m/s applies brakes and brings the car to rest in 20s. (i) (ii) (iii) Q10. (i) (ii) (i) (ii) What would be the acceleration of the car? (a) (b) (c) (d) + 2 m/s2 − 2 m/s2 − 0.5 m/s2 + 0.5 m/s2 The attained acceleration is also known as : (a) (b) (c) (d) positive acceleration retardation constant acceleration zero acceleration Which physical quantity is measured by the area under the velocity time graph ? (a) (b) (c) (d) time acceleration distance speed​

Answer 1

Answer:

0.5 m/s2

Explanation:

U (initial velocity) = 10 m/s

V (final velocity) = 0 m/s

t (time taken) = 20s

a (acceleration) = (V – U) / t

a = 0 – 10 / 20

a = – 0.5 m/s2

Retardation = 0.5 m/s2

:)

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