Question

When a car driver travelling at a speed of 10m/s applies breaks and brings the car in rest in 20s what is the retradation

Answer 1

Explanation:

A car driver is traveling at a speed of 10m/s . He applied break and brings to the car to rest in 20s. we have to find retardation. therefore the acceleration is -1/2 on youth edition is 1/2

Answer 2

Answer:

$\bigstar{\bold{Acceleration\:=\:-0.5\:m/s^{2} }}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 0 m/s
• Time taken = 20 s

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Retardation of the body (a)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ By the first equation of motion

  v = u + at

→ Substituting the datas, we get

  0 = 10 + a × 20

  a = -10/20

$\boxed{\bold{Acceleration\:=\:-0.5\:m/s^{2} }}$

→ Here acceleration is negative since it is retardation or deceleration.

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The three equations of motion are

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as