Question

when a car driver travelling at a speed of 10m/s applies brakes and brings the car to rest in 20 seconds, then the acceleration will be?

Answer 1

Answer:

-0.5 m/s^2

Explanation:

u=10m/s

t=20 s

v=0

By Newt.'s 1st Eq^n,

v=u+at

Since the breaks produce a deceleration,

v=u-at

0=10-a20

-20a= -10

a= -10/-20

a=0.5 m/s^2

Acc. = -(0.5) m/s^2