Question

When a car is stopped by applying break it stops after traveling a distance of 100m if speed of car is halved same retarding acceleration is applied then it stop after traveling a distance

Answer 1

Explanation:

let initial velocity X

X=at

so a=t/X

now second equation

X/2=at. ( both time are different)

2t/X=a

equating

2t/X=t/X

2t=t

so time becomes double