Math, asked by Sweetanalysie, 11 months ago

when a car travel at a speed of 60km/he applies brake it comes to rest in 15s then the retardation of the car is​

Answers

Answered by Anonymous
4

Initial velocity of the car (u) = 60km/hr^2 = 16.67 m/s^2

Final velocity (v) = 0 m/s

Time = 15s

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Use this equation

v = u + at

0 = 16.67 + a(15)

15 a = -16.67

15 will shift

Divide it

a = - 1.12 m/s^2

The retardation of the car = - 1.12 m/s^2

Answered by Bᴇʏᴏɴᴅᴇʀ
1

ANSWER:-

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Given:-

• Intial velocity of the car (u) = \bf{60km/hr}

\bf{\implies{16.67 m/s^2}}

Final velocity (v) = \bf{0 m/s}

Time = \bf{15s}

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SOLUTION:-

We know:-

\boxed{\bf{v = u + at}}

• Putting the values:-

0 = 16.67 + a[15]

0 = 16.67 + 15a

15 a = -16.67

a = {\bf{\frac{-16.67}{15}}}

a = - 1.11133 m/s^2

\implies{\bf{-1.12 \: m/s^2}}

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Therefore, the Retardation of the car is:

\bf{- 1.12 m/s^2}

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