When a certain amount of octane, C8H18, is burnt completely, 7.04 gm Co, is formed. What is the
weight of H2O formed, simultaneously?
(A) 1.62 gm
(B) 6.48 gm
(C) 3.24 gm
(D) 2.28 gm
just tell the answer.
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Answer:
3.24 is your answer
Explanation:
C8H17 + O2 ---------------> CO2 + H20
THEREFORE BALANCING THE EQUATION, WE
GET
C8H17 + 25/2O2 ---------------> 8CO2 + 9H20
Weight of CO2 = 7.04gm
Therefore,
nCO2/8 = nH20/9
7.04/44/8 = x/18/9
Solve for x,
x = 3.24 gms.
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