When a certain electric motor is operated for 30min it consume 0.75kWh of energy. During that time its total energy loss is 300j. What is the efficiency of the motor and how many joules of work does it perform in 30 min
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Explanation:
in 1/2 h work done = 750*3600 J=2700000 J
loss = 300 J
work output =(2700000-300)J=2699700J
efficiency = 2699700/2700000*100=99.98%(ans)
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