When a certain force acts on a moving object for 5.0 s, the object's momentum changes by 35 kg.m/s. What is the magnitude of this force?
Answers
Answer: Momentum (P) is equal to mass (M) times velocity (v). But there are other ways to think about momentum! Force (F) is equal to the change in momentum (ΔP) over the change in time (Δt). And the change in momentum (ΔP) is also equal to the impulse (J)
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The magnitude of the force acted on the object is 7 N.
Given:
A certain force acts on a moving object for 5.0 s and the object's momentum changes by 35 kgm/s.
To Find:
The magnitude of the force acted on the object.
Solution:
We are required to find the magnitude of the force acted on the object.
The force, momentum, and time relation are given by
Force, F = dp/dt -------()
where, dp = change in momentum
dp = 35 kgm/s
dt = 5 secs = change in time
By substituting the values of change in momentum and change in time in equation(1) we get
Force, F = 35/5
F = 7 kgm/s² or N
Therefore, The magnitude of the force acted on the object is 7 N.
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