When a certain number is divided by 2,there is a remainder Of 1.When the same number id divided by 3,4 and 5,there are remainders of 2,3 and 4,respectively.What is the smallest positive number that can be satisfied with the given conditions?
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If you add one to the number the resulting number is divisible by LCM (2,3,4,5) that is 60
=60-1
=59
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Answer:
when 2 is divided by 2 the remainder is 2 and the smallest positive number is 2
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