Question

When a certain two digits number is divided by the number obtained by
reversing the digits, the quotient is 2 and remainder is 7 . If the number is
divided by the sum of its digits the quotient is 7 and the remainder is 6. Find
the product of the digits of the original number

Answer 1

Answer:

Take 2 digit number as 'ab'

we can write it as 10a+b

now case 1

10a+b divided by 10b+a

10a+b=(10b+a)*2 + 7

8a-19b=7 ..........take as eqn1

case 2

10a+b divided by a+b

10a+b=(a+b)*7+6

a-2b=6 ....... eqn 2

solving two equations

b=3

a=8

original number was 83

hence answer is 24

Step-by-step explanation:

Answer 2

Answer:

answer for the given problem is given