When a concave mirror is placed facing the Sun, the Sun’s rays converge to a point
10 cm from the mirror. Now, if you place a 2 cm long candles flame 20 cm away on
the principal axis of the mirror, where would you place a screen to obtain the image
of the candle? What would see the size of the image? Draw a ray diagram to justify
your answer.
Answers
Answered by
2
f= -10 cm (since image is formed at focus)
now u= -20cm ( i.e, the candle flame is at c)
the image would be at c and of the same size
now u= -20cm ( i.e, the candle flame is at c)
the image would be at c and of the same size
Answered by
4
f = -10 cm as distant object forms image at 10 cm
candle: u = -20 cm. h = 2cm v = ?
1/v + 1/u = 1/f
1/v = -1/10 - 1/(20) = -1/20
=> v = - 20 cm
We place the screen also at 20cm away from the mirror. (but on the other side of the principal axis, as image is inverted).
m = -v/u = - 20/20 = -1
Image is also of 2 cm long. but inverted.
candle: u = -20 cm. h = 2cm v = ?
1/v + 1/u = 1/f
1/v = -1/10 - 1/(20) = -1/20
=> v = - 20 cm
We place the screen also at 20cm away from the mirror. (but on the other side of the principal axis, as image is inverted).
m = -v/u = - 20/20 = -1
Image is also of 2 cm long. but inverted.
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kvnmurty:
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