When a coordination compound CrCl3. 6H2O is mixed with AgNO3, two moles of AgCl are precipitated per mole of compound. Write the structural formula and the IUPAC name of the complex. I didn't understand why 1 molecule of H2O is also removed along with Cl2. Experts, I need your explanation. Thank you!
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Since the options are not given, I am giving an assumed answer.
The correct answer could be - [CrCl(H₂O)₅]Cl₂.H₂O.
Since the question says that 2 mol of AgCl has been formed that means 2 Chlorine atoms have been removed from the coordination compound. So, they will stay outside the bracket and will react with AgNO₃ to give 2 mol of AgCl.
The structure of the complex will be octahedral. That means 6 ligands will be inside the coordination complex. So, 1 molecule of water will be removed.
The correct answer could be - [CrCl(H₂O)₅]Cl₂.H₂O.
Since the question says that 2 mol of AgCl has been formed that means 2 Chlorine atoms have been removed from the coordination compound. So, they will stay outside the bracket and will react with AgNO₃ to give 2 mol of AgCl.
The structure of the complex will be octahedral. That means 6 ligands will be inside the coordination complex. So, 1 molecule of water will be removed.
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