When a copper sphere is heated
percentage change
Is may
in an
Answers
Answered by
0
Answer:
=3 times the percentage change in radius Thus, maximum percentage change is observed in volume.
Explanation:
Answered by
0
Answer:
Maximum in volume
Explanation:
Let R be the radius of sphere, V its volume and ρ its density. Then,
ΔR=RαΔθ
and percentage change in radius
R
ΔR
×100=100αΔθ ....(i)
Now, ΔV=γvΔθ=3αvΔθ {∵γ=3α}
∴ Percentage increase in volume
=
V
ΔV
×100=300αΔθ ...(ii)
Again, ρ
= 1+γΔθ
ρ =
1+3αΔθ
ρ
∴Δρ=ρ−ρ
′ =ρ[1− 1+3αΔθ 1}
= 1+3αΔθ (3αΔθ)ρ
Percentage change in density
= ρ Δρ ×100=
1+3αΔθ
300αΔθ ...(iii)
From equations (i), (ii) and (iii), we see that the percentage change is maximum in volume.
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