Question

when a cricket ball is thrown vertically upward it reaches a maximum height of 5m when a gravitational force is equal to 10 M per second square

what was the initial speed of the ball

how much time is taken by the ball to reach the highest point




no silly answers

Answer 1

s=5 m
a=-10 m/s^2
v=0(at max. height final velocity is 0)
therefore,
v^2-u^2=2as
0-u^2=2*-10*5
u^2=100
u=10 m/s
and time;
v=u+at
0=10-10t
t=1s