Question

When a cricket ball is thrown vertically upwards, it reaches a maximum height of 5 metres.(a) What was the initial speed of the ball ?(b) How much time is taken by the ball to reach the highest point ? (g =10 m/ s^2)​

Answer 1

Solution :-

(a) At maximum height V = 0

So from the eqn, V² = U² – 2gh

We get, U = (2 × g × h)^½= ( 2 × 10 × 5)^½ = 10 m/s

(b) The time required to reach the max height

( t ) = U / g

= 10 / 10

= 1 sec