Question

When a cricket ball is thrown vertically upwards it reaches a maximum height of 5 metres ? What was the initial speed of the ball?(g=9.8m/s square)

Answer 1

Answer:

Explanation:

v=0m/s

h=5m

g=9.8m/s^2

(a) v^2=u^2+2gh

0^2=u^2+2(-9.8×5)

0=u^2-2×49

0=u^2-98

98=u^2

√98=u

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Answer 2

Answer:

Initial velocity, u =  ?

Final velocity, v = 0

Acceleration due to gravity, g = 10 m/s  

2

 

Height, h = 5 m

Using relation, for a freely falling body:

v  

2

=u  

2

+2gh

(0)  

2

=(u)  

2

+2×(−10)×5

0  = u  

2

- 100

u  

2

=100

So, u = 10 m/s

(b) Using relation v = u + gt

0 = 10 + (-10) t

-10 = -10t

t = 1 sec