When a cricket ball is thrown vertically upwards ,it reaches a maximum height in 5 metre(g=10 m/s2 . (1) what was the initial speed of ball. (2) how much time is taken by the ball to reach the highest point!
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Answer:
Explanation:-
S= 5m
v=0
u=u
a=10m/s
putting the values in equation
v^= u^2 +2as
0 = u^2 + 2 X 10 X 5
u = -10m( where negative sign indicates direction)
(2) now putting the values in equation
v = u + at
0 = -10 + 10 X t
t = 1 sec
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