When a cricket ball is thrown vertically upwards it reaches a maximum height of 5 metres ? What was the initial speed of the ball ? How much time is taken by the ball to reach the highest point ?(g=10m/s square)
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Answered by
23
V^2 = u^2 + 2as
0 = u^2 - 2*g*5
u = 10m/s
the initial speed of the ball was 10 m/s
V = u + at
0 = 10 - gt
t = 1 sec
time taken by the ball to reach the highest point is 1 second.
0 = u^2 - 2*g*5
u = 10m/s
the initial speed of the ball was 10 m/s
V = u + at
0 = 10 - gt
t = 1 sec
time taken by the ball to reach the highest point is 1 second.
Answered by
11
Answer:
Explanation:V^2 = u^2 + 2as
0 = u^2 - 2*g*5
u = 10m/s
the initial speed of the ball was 10 m/s
V = u + at
0 = 10 - gt
t = 1 sec
time taken by the ball to reach the highest point is 1 second.
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