Question

When a cricket ball is thrown vertically upwards, it reaches a maximum height of 5 metres.

(a) What is the initial speed of the ball ?

(b) How much time is taken by the ball to reach the highest point ? (g= 10 m s-2 )

Answer 1

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S= 5m
v=0
u=u
a=10m/s

putting the values in equation

v^= u^2 +2as

0 = u^2 + 2 X 10 X 5

u = -10m( where negative sign indicates direction)

***(2) now putting the values in equation

v = u + at

0 = -10 + 10 X t

t = 1 sec

HOPE IT WILL HELP YOU

Answer 2

The above answer is correct.

The only error is that the 1st equation he used should not be v^2= u^2* 2as

It should be : v^2= u^2* 2gh where ‘g’ is the acceleration due to gravity and ‘h’ is height.