Question

when a cricket ball thrown vertically upwards, it reaches a maximum height of 5 M. a)What was the initial speed of the ball?b) how much time is taken by the ball to reach the maximum height? The value of g is 10 metre per second square

Answer 1

hiiii

v=0m/s

h=5m

g=9.8m/s^2

(a) v^2=u^2+2gh

0^2=u^2+2(-9.8×5)

0=u^2-2×49

0=u^2-98

98=u^2

√98=u

9.8m/s=u

(b) v=u+gt

0=9.8+9.8t

-9.8=9.8t

-9.8÷9.8=t

1s=t

Answer 2

hello user...........

here is your answer......

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ACCORDING TO THE QUESTION,

A CRICKET BALL IS THROWN VERTICALLY UPWARDS , IT REACHES THE MAXIMUM HEIGHT OF 5 METERS

MAXIMUM HEIGHT  = 5 M

BY USING THE FORMULA ,

   2u/g

   2 x u/10= 5

   2 x u =50

   u = 50/2

   u = 25

INITIAL VELOCITY = 25 M/S

THE TIME TAKEN TO REACH THE MAXIMUM HEIGHT IS

    U/G

    25/10

    2.5 SECONDS.

HOPE MY ANSWER WILL HELP U

THANK  Q

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