Question

When a current carrying straight conductor of length 2m,moves perpendicular to magnetic induction field strength of 2 tesla with velocity 10m/s,find emf induced in volts

Answer 1

ஜ۩۞۩ஜ ӇЄƳƛ MƛƬЄ ஜ۩۞۩ஜ

Your answer...

Induced emf,

e = vlB

e = 10 x 2 x 2

e = 40 V

нσρє нєℓρѕ ! ❤️❤️

Answer 2

e = Bvl

=2*10*2

=40V

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