Question

when a current changes from +2A to -2A in 0.05 second an EMF of 8 volt induced in a coil the coefficient of self induction of the coil is
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Answer 1

Answer:

Explanation:

e=-L×di÷dt

8=L×[2-(-2)]÷0.05

8×0.05=L[2+2]

0.4=L×4

L=0.4÷4

L=0.1 henry