when a current of 0.15amperes passed a through a salt of meyal for 150 minutes 0.783g of metal was deposited .find the valency of the metal
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Answer:
Correct option is
B
2
Given mass=0.788g
Current(I) =1.5ampere
Time(t)=15min=900sec
Atomic Mass=112
Formula:-
Mass=
F
E
×I×t [E=EquivalentWeight,F=Faraday=96500C,1C=1ampere×1sec]
∴0.788g=
96500C
E
×1.5×900(C)
∴
1.5×900
0.788×96500
=E
∴E=56.3
Equivalent Weight=
Valency
Atomicmass
∴Valency=
Equivalentweight
Atomicmass
=
56.3
112
=2
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