Question

When a current of 4.0 A passes through a certain resistor for 10 minutes, 2.88 x 10^4J of heat are produced.
Calculate :
(a) the power of the resistor.
(b) the voltage across the resistor.
​

Answer 1

Answer:

We know if I A current flows through R ohm resistance along t seconds then the produced heat is

H=(I^2)*R*t

Here H=2.88*10^4 J

I=4 A

t=10 min=600 second

So, R=H/{(I^2)*t}

=2.88*10^4/{(4^2)*600}

=3 ohm

So the value of resistance is 3 ohm

Again we know V=IR

V=voltage

I=current

R=resistance

So, V=4*3=12 volt.

Here the power of the resistance is

=P=VI=12*4=48 watt.

Answer 2

Answer:

Given: I = 4amp, t = 10min = 10 x 60 = 600sec, H = 2.88 x 104J

(a) We have

H = I2RT

28800 = 42 x R x 600

R = 3ohms

We know that

P = I2 x R

= 42 x 3

P = 48W

(b) V=?

We know that

V = IR

V = 4 x 3

V = 12V

Explanation:

hope hope this answer help you