When a current of 4.0A passes through a certain resistor for 10 minutes,2.88X10^4 J of heat are produced. CALCULATE: 1:the power of the resistor 2:the voltage across the resistor plzzzzzzz answer fast.
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t=10min=600sec
I=4A
H=2.88×10⁴J
H=I²Rt
R=2.8×10⁴/4×4×600
R=18ohm
P=I²R
=4×4×18
=288w
V=RI
=18×4
=72V
I=4A
H=2.88×10⁴J
H=I²Rt
R=2.8×10⁴/4×4×600
R=18ohm
P=I²R
=4×4×18
=288w
V=RI
=18×4
=72V
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