Question

When a current of 4 ampere passes through register for 10 minutes 2.88 into 10 raise to power 4 joule heating produce calculate the power of resistor

Answer 1

$\mathtt{\huge{ \fbox{Solution :)}}}$

Given ,

Current (I) = 4 amp

Time (t) = 10 min or 600 sec

Heat (h) = 2.88 × (10)^4 joule

We know that ,

The Joule's law of heating states that the heat produced in a resistor is directly proportional to the

(i) Square of current which flows through the resistor

(ii) Resistance

(iii) Time for which the current is flows through the resistor

$\mathtt{ \large \fbox{H = {( I)}^{2} Rt}}$

Thus ,

2.88 × (10)^4 = (4)² × R × 600

288 × (10)^4 = 16 × R × 6 × (10)^4

R = 288/16 × 6

R = 72/4 × 6

R = 72/24

R = 3 Ω

Hence , the resistance is 3 Ω

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