When a current of 4A passes through a certain resistor for 10min, 2.88 x 10^4 J of heat are produced. Calculate (a) power of the resistor (b) the voltage across the resistor. Plz answer fast with solution
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Work done = Heat = 2.88*104 J
Time = 10 min = 600 sec
Power = Work Done/ Time = 2.88*104 J / 600 sec = 48 W
I = 4A
P = IV
V = P/I = 48 / 4 A = 12 V
Time = 10 min = 600 sec
Power = Work Done/ Time = 2.88*104 J / 600 sec = 48 W
I = 4A
P = IV
V = P/I = 48 / 4 A = 12 V
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