Physics, asked by ashutosh8888, 1 year ago

When a current of 5ma is passed through a galvanometer?

Answers

Answered by Kinggovind021

2

Explanation:

G=15 ohms

Ig=5 x 10^-3 A

V=10 V

R=V/Ig-G

10/5/1000-15

10 x 1000/5-15

2000-15=1985 ohms

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