Question

when a cyclist travelling at a speed of 10 metre per second applies the break and bring the cycle to the rest in 20 second find the retardation produced ​

Answer 1

$\sf{\large{\underline{\underline{EXPLANATION:}}}}$

★Given,,

• Initial speed of the cyclist,u=10m/s

• Final speed of the cyclist,v=0m/s

• Time taken,t=20s

★To find,,

• Retardation of the cyclist,a=??

★Using 1st equation of motion,,

$</strong><strong>\</strong><strong>s</strong><strong>f</strong><strong>{\boxed{</strong><strong>v</strong><strong>=</strong><strong>u</strong><strong>+</strong><strong>at</strong><strong>}}$

$\</strong><strong>s</strong><strong>f</strong><strong>{\</strong><strong>i</strong><strong>m</strong><strong>p</strong><strong>l</strong><strong>i</strong><strong>e</strong><strong>s</strong><strong>{</strong><strong>0</strong><strong>=</strong><strong>1</strong><strong>0</strong><strong>+</strong><strong>2</strong><strong>0</strong><strong>a</strong><strong>}}$

$\sf{\implies{</strong><strong>-</strong><strong>1</strong><strong>0</strong><strong>=20a}}$

$\sf{\implies{</strong><strong>\</strong><strong>c</strong><strong>a</strong><strong>n</strong><strong>c</strong><strong>e</strong><strong>l</strong><strong>\</strong><strong>d</strong><strong>f</strong><strong>r</strong><strong>a</strong><strong>c</strong><strong>{</strong><strong>-10</strong><strong>}</strong><strong>{</strong><strong>2</strong><strong>0</strong><strong>}</strong><strong>=a}}$

$\sf{\implies{</strong><strong>-</strong><strong>0</strong><strong>.</strong><strong>5</strong><strong>=a}}$

★Therefore, retardation of the cyclist,,

$\sf{\</strong><strong>b</strong><strong>o</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>a</strong><strong>=</strong><strong>-</strong><strong>0</strong><strong>.</strong><strong>5</strong><strong>m</strong><strong>s</strong><strong>^</strong><strong>{</strong><strong>-2</strong><strong>}</strong><strong>}}$

$\rule{200}2$

★Hope it helps★

Answer 2

Answer:

A cyclist is traveling at a speed of 10m/s per second

e.g., initial velocity , u = 10m/s

He applied break and the cycle to rest in 20s.

so, time taken to stop the car = 20s

we have to find retardation.

final velocity of car , v = 0 m/s

use formula, v = u + at

0 = 10 + a20

a = -1/2 m/s² [sign shows retardation ]

Morerover

acceleration = -0.5 m/s²

Negative acceleration is also known as deceleration or retardation.

Therefore,

Deceleration/retardation = 0.5 m/s²

Explanation:

I hope this helped.