Physics, asked by hrikchaudhuri01, 3 months ago

When a dc voltage of 200V is applied to a coil of self-inductance (2\sqrt{3} /π) H, a current of 1 A flows through it. But by replacing dc source with ac source of 200 V, the current in the coil is reduced to 0.5 A. Then the frequency of ac supply is
A. 100 Hz
B. 75 Hz
C. 60 Hz
D. 50 Hz

Answers

Answered by anitakumari0688
0

Answer:

When a dc voltage of 200 V is applied to a coil of self inductance (2√3/π)H a current of 1A flows through it.

Explanation:

answer answer is 100 Hz

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